((-3x^5/4x^-2)^-4)(-9x^2/8x^-5)^3

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Solution for ((-3x^5/4x^-2)^-4)(-9x^2/8x^-5)^3 equation: 


D( x )

x = 0

x^-2*((-3*x^5)/4) = 0

x = 0

x = 0

x^-2*((-3*x^5)/4) = 0

x^-2*((-3*x^5)/4) = 0

-3/4*x^3 = 0 // : -3/4

x^3 = 0

x = 0

x in (-oo:0) U (0:+oo)

(x^-2*((-3*x^5)/4))^-4*(x^-5*((-9*x^2)/8))^3 = 0

-9/2*x^-21 = 0 // : -9/2

x^-21 = 0

x naleu017Cy do O

x belongs to the empty set

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